oracle sql 取连续数段
bigzhu
posted @ Aug 18, 2010 01:02:10 AM
in oracle
, 3673 阅读
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需求
表结构如下,作了简化
CREATE TABLE "INVOICE"."POOL"
(
"TAX_NBR" VARCHAR2(20 BYTE),--税务发票号
"STAFF_ID" NUMBER(20,0),--工号
)
tax_nbr 为税务发票号,staff_id 为持有该发票号的工号. tax_nbr在一段内连续.
要求统计时,按工号持有的号段统计出来
可能有这样的数据:
staff_id tax_nbr 1 1 1 2 1 3 1 7 1 8 1 9
要求统计出:
staff_id tax_begin_nbr tax_end_nbr 1 1 3 1 7 9
-
思路一
写程序把每条记录按顺序取出,比较每条是否等于上一条+1,不等于,那就反回一条统计.
然后接着比较......
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思路二
一条select sql 就搞定了
SELECT staff_id, min(tax_nbr), max(tax_nbr)
FROM (SELECT staff_id,
tax_nbr,
TO_NUMBER(tax_nbr) -
(ROW_NUMBER() OVER(PARTITION BY staff_id ORDER BY TO_NUMBER(tax_nbr))) DIF
FROM pool)
GROUP BY staff_id, DIF;
Aug 18, 2010 06:06:17 PM
发现一个问题:
因为tax_nbr原本是varchar2的关系,"OVER (PARTITION BY staff_id ORDER BY tax_nbr)"并不能完全得到想要的结果,在tax_nbr的值上两位数后排序就会以字符排序的方式进行,而非数字.也就是说,"1"后面会是"10","11",而不是"2".
要想达到预期效果,需要改成"ORDER BY TO_NUMBER(tax_nbr)",或者干脆直接把这个字段设置成number类型,而不是varchar2。
Aug 19, 2010 06:31:31 AM
谢谢指正,已经先改了,等有空好好研究下 verchar2 的排序.
不能改成 number 类型是因为业务需要,税务发票有些前置0,例如 0012 之类,还不能将前面的0去掉,只能用varchar2
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